(Math | Calculus | Derivatives | Table Of)

arcsin x = 1 (1 - x^{2}) | arccsc x = -1 |x| (x^{2} - 1) |
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arccos x = -1 (1 - x^{2}) | arcsec x = 1 |x| (x^{2} - 1) |

arctan x = 1 1 + x^{2} | arccot x = -1 1 + x^{2} |

Derivative of arctan(x). Let's use our formula for the derivative of an inverse function to find the deriva tive of the inverse of the tangent function: y = tan−1 x The Derivative of Arctan x. If y = tan

^{-1}x, then tan y = x. Taking the derivative of the second expression implicitly gives: sec^2y dy/dx = 1. solving for the derivative The derivative of y=arctanx is y'=11+x2 . We can derive this by using implicit differentiation. Since inverse tangent is hard to deal with The derivative of arccos x. The derivative of arctan x. The derivative of arcsec x. The derivative of arccsc x. The derivative of arccot x.
How do you find the derivative of arctan?

Is Arctan differentiable?

y =

**arctan**( x ) is**differentiable**for all real number x . , for all x
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